What is the electron pair geometry of IC14?

To determine the electron pair geometry of IC14, it's important to analyze the arrangement of electron pairs around the central iodine atom. Iodine typically has seven valence electrons and, when bonded to carbon atoms, it can exhibit coordination numbers that influence its geometry.

In the case of IC14, where iodine is bonded to four carbon atoms, we recognize that each carbon typically forms a single bond with iodine. This results in four bond pairs around the iodine. Additionally, iodine possesses three lone pairs of electrons. The positions of these lone pairs and bonding pairs dictate the overall geometry.

The square planar configuration is achieved when there are four bonded atoms and two lone pairs of electrons around the central atom (iodine in this case). The bonded carbon atoms will be positioned at the corners of a square, while the lone pairs occupy the axial positions, allowing for a stable arrangement that minimizes electron pair repulsion, according to VSEPR theory.

Thus, with the presence of four bond pairs and two lone pairs, the electron pair geometry of IC14 is indeed square planar, supporting the answer provided.